Math, asked by viswanand5624, 10 hours ago

Salary of A,B,C are in the ratio 3,2,1.salary of A and B together is Rs 60000.by what % is salary of A more than C

Answers

Answered by Uvaish04
0

Answer:

200%

Step-by-step explanation:

salary in ration 3:2:1

let,

3x+2x+1x = 60000

6x = 60000

x = 60000/6

x = 10000

a = 3x = 3×10000 = 30000

b = 2x = 2×10000 = 20000

c = 1x = 1×10000 = 10000

% of A more than C =

30000 - 10000

10000 × 100

= 20000

100

= 200%

Answered by prayasraj999
0

Step-by-step explanation:

A=3x

B=2x

C=x

in question A+B=60000

3x + 2x= 60000

5x= 60000

x= 12000

then,

a is 36000

b is 24000

c is 12000

% of a more than c is= ( salary of a- salary of c) ÷ salary of c × 100%

36000 - 12000 ÷ 12000 ×100%

24000÷ 12000×100%

2×100%

200%

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