Salim has a paper route. In the winter time, he puts his newspapers on a toboggan to pull them through the snow. The combined mass of the papers and the toboggan is 24 kg. The coefficient of static friction between the toboggan and the snow is 0.18. The coefficient of kinetic friction between the toboggan and the snow is 0.10.
a. With how much force must Salim pull in order to get the toboggan to start moving?
b. How much force is needed to keep the toboggan moving at a constant speed? Please add steps
Answers
Answer:
pls mark me as brainliest if you are satisfied
Explanation:
F = m a
If your force is positive, your acceleration is positive. (negative mass does not occur in this subject)
HOWEVER
That says NOTHING about the magnitude or direction of VELOCITY.
If the car is headed North and puts the brakes on, the force will be South.
However until the speed reaches zero, the velocity remains North.
Damon
Jan 7, 2014
Find Fn by doing: Fn = mg, then, to find the minimum force required to start moving it, use Fk = Fn*Us ... (Us being static Friction).
To find the amount needed to keep it at a constant velocity,
use: Fs = Fn*Uk.
In your case, it would be:
Fk = 235.2*0.18 = 42.3N, to get it moving
Fs = 235.2*0.10 = 23.52, to keep it at a constant velocity.
Answer:
1 )F = m a
If your force is positive, your acceleration is positive. (negative mass does not occur in this subject)
HOWEVER
That says NOTHING about the magnitude or direction of VELOCITY.
If the car is headed North and puts the brakes on, the force will be South.
However until the speed reaches Find Fn by doing: Fn = mg, then, to find the minimum force required to start moving it, use Fk = Fn*Us ... (Us being static Friction).
2) To find the amount needed to keep it at a constant velocity,
use: Fs = Fn*Uk.
In your case, it would be:
Fk = 235.2*0.18 = 42.3N, to get it moving
Fs = 235.2*0.10 = 23.52, to keep it at a constant velocity.zero, the velocity remains North.