Question

Sally has only 10-pence and 50 pence coins in her purse. She has 21 coins altogether with a total value of $5.30. Calculate how many of each coin type does she have?

Answer 1

Answer:

13 and 8

Step-by-step explanation:

10x+50(21-x)=530

10x+1050-50x=530

-40x=530-1050

-40x=-520

x=-520/-40

x=13

10 cent coin 13

50 cent coin 8

Answer 2

No.of 10 pence coins Sally has is 13 and No.of 50 pence coins Sally has 8.

Given :

Total no.of coins Sally has = 21

Total value = $5.30

To find :

No.of each coin type she has

Solution :

Let the no.of 10 pence coins be x

Hence, the no.of 50 pence coins = 21-x

$5.30 = 530 pence

According to the problem,

=> 10x + 50(21-x) = 530

=> 10x + 1050 - 50x = 530

=> 1050 - 40x = 530

=> 1050 - 530 = 40x

=> 520 = 40x

=> x = 520/40

= 13

x = 13

21 - x = 21 - 13 = 8

Hence, No.of 10 pence coins Sally has is 13 and No.of 50 pence coins Sally has 8.

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