Question

Sally spins a fair spinner numbered 1 - 5 and rolls a fair dice. What is the probability of spinning a multiple of 3 and rolling a factor of 10?

Answer 1

Answer: Probability of obtaining a multiple of 3 and a factor of 10 is given by

\frac{1}{10}

10

1

Step-by-step explanation:

Since we have given that

There is a fair spinner numbered 1-5 and a fair dice

Total number of outcomes of fair spinner = 5

Total number of outcomes of a fair dice = 6

Let Event A: Getting a multiple of 3 on a spinner

Event B: Getting a factor of 10 on a fair dice

The possible outcomes of multiple of 3 on a spinner is

33

The possible outcomes of factor of 10 on a fair dice are

1,2,51,2,5

So,

P(A)=\frac{1}{5}P(A)=

5

1

and

P(B)=\frac{3}{6}=\frac{1}{2}P(B)=

6

3

=

2

1

Since A and B are independent events so,

\begin{gathered}P(A\ and\ B)=P(A).P(B)\\\\P(A\ and\ B)=\frac{1}{5}\times \frac{1}{2}\\\\P(A\ and\ B)=\frac{1}{10}\end{gathered}

P(A and B)=P(A).P(B)

P(A and B)=

5

1

×

2

1

P(A and B)=

10

1

Hence, Probability of obtaining a multiple of 3 and a factor of 10 is given by

\frac{1}{10}

10

1