Question

Salma borrowed Rs 1875 from the Mahila Samita for buying a sewing machine. If the rate of interest is 4% p.a then calculate: i) the amount due at the end of the first year ii) the interest in the second year iii) the total interest paid if she repays at the end of the 2nd yr pls give the answers ast fast as possible

Answer 1

★ Given :

Money borrowed by Salma = ₹1875

Rate of interest = 4%

★ To find :

i) Amount due at the end of first year..

ii) the interest paid in second year..

iii) total interest paid if she repays after 2 years..

★ Solution :

We know that ,

$SI = \frac{P \times R \times T}{100}$

P = 1875

R = 4%

T = 1 year

By putting the values..

$\implies \frac{1875 \times 4 \times 1}{100}$

$\implies \frac{\cancel{7500}}{\cancel{100}}$

SI = ₹75 ..

Amount = Principal + Interest ..

= 1875 + 75

$\purple{\leadsto 1950}$

ii) Interest paid in the second year =

Principal (Amount after first year) = 1950

T = 1 year

R = 4%

By putting the values in formula..

$\implies \frac{1950 \times 4 \times 1}{100}$

$\implies \frac{7800}{100}$

Therefore , Interest paid in second year = ₹ 78

iii)Total interest paid after two years =

P = 1875

T = 2

R = 4

By putting values in formula..

$\implies \frac{1875 \times 4 \times 2}{100}$

$\implies \frac{15000}{100}$

→ therefore , interest paid at the end of two years = ₹150..