Math, asked by Anonymous, 6 months ago

Salut!!✌
Help me please.......
Simplify:-
( \frac{1}{2} y {}^{2}  -  \frac{1}{3} y - 1) - ( \frac{1}{3} y {}^{2}  -  \frac{1}{2} y - 3) - ( \frac{1}{4} y {}^{2}  -  \frac{1}{3} y -  \frac{1}{2} )
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Answers

Answered by parin7970
2

the above pic is the solution for your question

Attachments:
Answered by Anonymous
38

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 {\longmapsto\mathtt{( \frac{1}{2} y {}^{2} - \frac{1}{3} y - 1) - ( \frac{1}{3} y {}^{2} - \frac{1}{2} y - 3) - ( \frac{1}{4} y {}^{2} - \frac{1}{3} y - \frac{1}{2} )}}

{ \longmapsto{ \mathtt{ \frac{1}{2} {y}^{2}  -  \frac{1}{3}y - 1  -  \frac{1}{3}  {y}^{2}   +  \frac{1}{2}y +   3 - \frac{1}{4}   {y}^{2}  +  \frac{1}{3}  y +  \frac{1}{2} }}}

{ \longmapsto{ \mathtt{ \frac{1}{2}  {y}^{2}  -  \frac{1}{3} {y}^{2}  -  \frac{1}{4} {y}^{2}   -  \frac{1}{3} y  + \frac{1}{2}  y +  \frac{1}{3}y - 1 + 3 +  \frac{1}{2}  }}}

{ \longmapsto{ \mathtt{ {y}^{2}( \frac{1}{2} -  \frac{1}{3}   -  \frac{1}{4}  ) - y( \frac{1}{3}  -  \frac{1}{2} -  \frac{1}{3}  ) - 1 + 3 +  \frac{1}{2} }}}

{ \longmapsto{ \mathtt{ {y}^{2} (\frac{(6 - 4 - 3)}{12}) - y( \frac{(2 - 3 - 2)}{6}  )(  \frac{(- 2 + 6 + 1)}{2} )}}}

{ \longmapsto{ \mathtt{ {y}^{2}(  \frac{(6 - 7)}{12} ) - y( \frac{(2 - 6)}{6})(  \frac{( - 2 + 7)}{2} ) }}}

{ \longmapsto{ \mathtt{ {y}^{2} (\frac{ - 1}{12} )  - y( \frac{ - 4}{6} ) +  \frac{5}{2} }}}

{ \longmapsto{ \mathtt{ \frac{ - 1}{12}  {y}^{2}  +  \frac{4}{6}y +  \frac{5}{2}  }}}

{ \longmapsto{ \mathtt{ \frac{ - 1}{12}  {y}^{2}  +  \frac{2}{3}y +  \frac{5}{2}  }}}

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