Question

SALUT...IT'S A PUZZLING QUESTION FOR YOU..........

'' THERE ARE THREE GUD FRNDS. THEY ARE GOING TO RESTAURANT.THEY ORDERED THREE SAMOSAS... ONE SAMOSA IS OF 15 /-..ND THREE SAMOSAS ARE OF 45/-....BUT RASTAURANT OWNER IS FRND OF THEM.........HE RETURN 5/- TO THEM IN HANDS OF WAITER......BUT WAITER IS DISHONEST ..HE TAKE 2/- FOR OWN AND RETURN THREE RUPEES TO THREE FRNDS...TEENO FRNDS KA SAMOSA 14 /- M AYA...
SO.,,14 +14+14 =42....AND WAITER KE PAAS 2/- THE ..SO ..42+2=44.....ABB TELL ME THAT WHERE IS 1/- GUYS???...FRSTLY 45 /- THE ....LEKIN ONE RUPEE KHA GYA?

Answer 1

${Answer :-}$

Are yaar,
The waiter returned 3 rupees and kept 2 rupees with him,.

So, when you add, 42 + 3 = 45, not 42 +2 =44.

So,.. It's simple.

Hope this helps,.

If helps, please mark it as brainliest ^_^

Answer 2

Hey Mate!!

How's uh?

This is simple though:

When, the waiter returned only 3 rupees and kept 2 rupees with him then:

→42 + 3 = 45

Cause, he give then only 3 not 5

That's why, we add only 3 rupees.

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