Question

Salute u guys if u solve this

Answer 1

( x- 3)( x- k ) =x× x× x× -k× -3× -k

Answer 2

Answer:

Step-by-step explanation:

Suppose f(x) = x^2 - kx + 6

If x - 3 is a factor of above equation then f(3) should be zero

So Replacing x by 3

               f(3) = 3^2 - 3k + 6 = 0

                        9 - 3k + 6 = 0

                                    -3k = -15

                                      k = 5

Now we have to prove that x - k is a factor of  x^2 - 7x + 10

x - k  = x - 5

suppose; f(x) = x^2 - 7x + 10

If x - 5 is a factor of x^2 - 7x + 10 then f(5) must be zero

               Replace x with 5

               f(5) = (5)^2 - 7(5) + 10

                       = 25 - 45 + 10

                       = 10 - 10

                       = 0

Hence x - k is a factor of x^2 - 7x + 10 where k = 5