Salve the equation : x2-(√3 +1) x+√3=0.
Answers
Answered by
0
Answer:
√3 and 1
Step-by-step explanation:
We have,
x
2
−(
3
+1)x+
3
=0
⇒x
2
−(
3
+1)x=−
3
⇒x
2
−2(
2
3
+1
)x+(
2
3
+1
)
2
=−
3
+(
2
3
+1
)
2
⇒(x−
2
3
+1
)
2
=
4
−4
3
+(
3
+1)
2
⇒(x−
2
3
+1
)
2
=(
2
3
−1
)
2
⇒x−
2
3
+1
=±
2
3
−1
⇒x=
2
3
+1
±
2
3
−1
⇒x=
3
,1
Hence, the roots are
3
and 1.
Answered by
0
Answer:
x^2-(√3+1)x+√3
=x^2-√3x-x+√3
=x(x-√3)-1(x-√3)
=(x-√3)(x-1)
either, x-√3=03 , x=√3
or, x-1=0 ,x=1
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