Question

salve the following simulteneous equation
3x-3y = 8, 3x + y = 2​

Answer 1

Answer:

x=7/6

and y =-3/2

Step-by-step explanation:

3x-3y,=8_____1

3x+y=2______2

from eq 2

y=2-3x

value of y put in the eq 1

3x-3(2-3x)=8

3x-6+9x=8

12x-6=8

12x=8+6

12x=14

x=14/12

x=7/6 _____________

now put this value any eq 1 or 2

3*7/6+y=2

21/6+y=2

y=2-21/6

y=12-21/6

=-9/6

y=-3/2,________

Answer 2

Answer:

x=7/6 and y=-3/2

Step-by-step explanation:

3x-3y=8........1

3x+y=2..........2

multiply 3 in eqn 2,

9x+3y=6.....3

Add eqn 3 and 1,

9x+3y=6

+

3x-3y=8

we get,

12x=14

x=

$\frac{14}{12}$

means,

$\frac{7}{6}$

put value of x in eqn 2,

we get y=-3/2

Hope helped.......