Math, asked by tejas196844, 18 days ago

Sam borrowed some mons ey from his
friend at simple interest of 6% per
annum . he returned his friend rs.
15600. after how much time did sam
return the money if he borrowed
rs.12000?​

Answers

Answered by eshwarsahi01
1

Answer:

5 years

Step-by-step explanation: Principal (P) = 12,000 Rs

Rate (R) = 6% p.a.

Time (T) = ?

Amount = 15,600 Rs

so,

Interest (I) = Amount - Principal

Interest = 15,600 - 12,000

I = 3600

Since,

(P x R x T) ÷ 100 = I

 

Time = 5 years

Answered by MasterDhruva
5

Correct Question :-

Sam borrowed some money from his friend at rate of interest at 6% per annum . He returned his friend ₹15600. After how much time did Sam return the money if he borrowed ₹12000?

\:

Given :-

Principle :- ₹12000

Rate of interest :- 6%

Total Amount :- ₹15600

\:

To Find :-

The time taken to return the money back...

\:

Formula required :-

{\large \dashrightarrow \orange{\boxed{\tt \gray{Simple \: Interest + Principle}}}}

\:

How to do :-

Here, we are given with the principle amount, the rate of interest and the total amount given back at end of the time period. We are asked to find the time taken to return back the money. So, first we should find the simple interest of the sum by subtracting the total amount and the principle amount. The obtained answer will be the simple interest. Later, we can find the time taken by using the given formula. So, let's solve!!

\:

Solution :-

Simple Interest :-

{\tt \leadsto 15600 - 12000}

{\tt \leadsto Rs \: \: 3600}

\:

Now, we can find the time period by using the formula as we have found with simple interest.

Time :-

{\tt \leadsto \dfrac{3600 \times 100}{12000 \times 6}}

{\tt \leadsto \dfrac{3600 \times \cancel{100}}{\cancel{12000} \times 6} = \dfrac{3600 \times 1}{120 \times 6}}

{\tt \leadsto \dfrac{\cancel{3600} \times 1}{120 \times \cancel{6}} = \dfrac{600 \times 1}{120 \times 1}}

{\tt \leadsto \cancel \dfrac{600}{120} = \boxed{\tt 5 \: \: years}}

\Huge\therefore The time taken to return back the money is 5 years.

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\dashrightarrow Some related formulas :-

\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Simple \: Interest :- \dfrac{P \times R \times T}{100}} \\  \\ \bigstar \:  \sf{Principle :- \dfrac{SI \times 100}{R \times T}}  \\  \\\bigstar \:  \sf{Rate \: of \: Interest :- \dfrac{SI \times 100}{P \times T}}  \\  \\ \bigstar \:  \sf{Time :- \dfrac{SI \times 100}{P \times R}}\end{array}}

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