Question

Sam has been given a task to make a model of a boat that can float in salt water as well as fresh water. For this he first collects some water samples from the nearby beach and some from a river in two containers.
Now on the way, he missed to label the samples. The volume of sample A is 1 m3 and its mass is 1029 kg. Whereas the mass of the same volume of sample B is 1000 kg. Help Sam, to identify the beach sample (salt water) and the river sample (fresh water)
[Hint: River water is pure compared to seawater]
Sam has made a model boat of mass 1029 kg for trial, it displaces 1 m3 volume of salt water. Now, he takes the boat to the fresh water and it displaces 1.02 m3 volume, however, this time it sinks after a while. Help Sam to interpret the reason for the sinking and floating of the boat. Also suggest how he can make the boat float in fresh water as well.

Answer 1

Answer:sorrry i am not unnderstanding the question

Explanation:

Answer 2

Answer:

The sample A will be sea/ salt water and sample B will be river/ fresh water

Explanation:

The samples could be identified by comparing their densities. As salt water will be more dense than

freshwater.

Given:

Volume of sample A = 1 m3

Mass of sample A = 1029 kg

Volume of sample B = 1 m3

Mass of sample B = 1000 kg

To find:

Density of both samples

Calculations:

Density of sample A = mass/volume = 1029/1 = 1029 kg/m3

Density of sample B = mass/volume = 1000/1 = 1000 kg/m3

Density of sample A > Density of sample B