Sam is 3 times as old as Rob. If 15 is subtracted from Sam's age and 13 is added to Rob's age, their ages will be equal. How old is each now?
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Let Sam's age be x and Rob's age be y
=> x = 3y ----(1)
ATQ
x-15 = y + 13 ----(2)
Using (1) in (2)
3y - 15 = y + 13
=> 3y - y = 13 + 15
=> 2y = 28
=> y = 14
Using y =14 in (1), we get
x = 3×14 = 42
.
Sam's age = 42
Rob's age = 14
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