Question

Sam is 5 years older to his sister for years later he will be twice as old as his sister find the present ages​

Answer 1

Present Age,

Let Sister age=x years

Then Sam Age=(x+5) years

After 4 years

Sister Age=(x+4) years

Sam Age=(x+5+4) years

After 4 years sam is also 2×sister age after 4 years.

A/Q

2(x+4)=(x+5+4)

2x+8=x+9

2x-x=9-8

x=1

x is age of sister=1 years

X+5 is age of Sam=1+5=6 years

$\boxed{\mathtt{\huge{Sister=1\:years}}}$

$\boxed{\mathtt{\huge{Sam=6\:years}}}$