Question

Sam scored 30% marks but failed by 5 marks. If the required passing percentage was 40%, what was the maximum marks of the test conducted​

Answer 1

Answer:

This Can be solved algebraically as follows…

We assume total marks = x

1st Candidate scores 30% of x = 3x/10

Fails by 5 marks

So, minimum pass marks=( 3x/10) + 5

= (3x + 50) /10 …………(1)

2nd candidate scores 40% of x = 4x/10

He svores 10 more than minimum

=> minimum pass marks = (4x/10) - 10

= (4x-100) / 10 …………. (2)

(1)&(2) are eaqual

=> (3x+ 50)/10 = (4x- 100) / 10

=> 3x + 50 = 4x - 100

=> x = 150

=> minimum pass marks by (1)

=( 3x+50)/10

= (3 x 150 + 50) /10

=> 500/10

= 50 marks out of 150 is required to pass

So minimum pass percentage =

(50/ 150) x 100

= 100/3

= 33.3 %

Hence the answer.

Step-by-step explanation:

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Answer 2

Answer:

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