Sam scored 30% marks but failed by 5 marks. If the required passing percentage was 40%, what was the maximum marks of the test conducted
Answers
Answer:
This Can be solved algebraically as follows…
We assume total marks = x
1st Candidate scores 30% of x = 3x/10
Fails by 5 marks
So, minimum pass marks=( 3x/10) + 5
= (3x + 50) /10 …………(1)
2nd candidate scores 40% of x = 4x/10
He svores 10 more than minimum
=> minimum pass marks = (4x/10) - 10
= (4x-100) / 10 …………. (2)
(1)&(2) are eaqual
=> (3x+ 50)/10 = (4x- 100) / 10
=> 3x + 50 = 4x - 100
=> x = 150
=> minimum pass marks by (1)
=( 3x+50)/10
= (3 x 150 + 50) /10
=> 500/10
= 50 marks out of 150 is required to pass
So minimum pass percentage =
(50/ 150) x 100
= 100/3
= 33.3 %
Hence the answer.
Step-by-step explanation:
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