Sam weighs 495 N. She climbs a flight stairs 6 m high going to the second floor of their two- storey house, what is Sam’s potential energy?
Answers
Answer:
Explanation:
Problem:
Sam weighs 495 N. She climbs a flight of stairs 6.0 m high going to the second floor of the two-storey house. What is Sam's potential energy at the second floor? Going down the stairs, Sam stops 2.0 m from the second floor. What is the change in her PE?
Note:
The formula for the Potential Energy is ( P.E. = m × g × h ) or ( P.E. = F × h ). The gravitational acceleration on Earth is 9.8 m/s² .
Given Data:
F ( Force ) = 495 kg ·m/s² or 495 N
h ( Height ) = 6 m
P.E. ( Potential Energy ) = ? unknown
Solution:
The formula for the Potential Energy is ( P.E. = F × h ).
P.E. = F × h
= 495 kg ·m/s² × 6 m
= 2,970 kg·m²/s²
= 2,970 J
Answer:
The potential energy is 2,970 kg·m²/s² or 2,970 J