समीकरण 2x^2-5x-3=0 का विवितकर ज्ञात कीजये और फिर मूलो की प्रकृति ज्ञात कीजिए। यदि वह वास्तविक है तो उन्हें ज्ञात कीजये। Please solve it ....
Answers
Answer:
1466
Step-by-step explanation:
hindi bhut muskil se samajh aata hai
Step-by-step explanation:
a)Givenequation:x2−79=x2+9x+1
/* subtract bothsides of the equation by x², we get */
\implies x^{2} - 79 - x^{2} = x^{2}+9x+1 - x^{2}⟹x2−79−x2=x2+9x+1−x2
\implies -79 = 9x + 1⟹−79=9x+1
\blue { ( Degree \: of \: the\: equation \:is \: 1 )}(Degreeoftheequationis1)
So, it \:is \:a \: Linear \: equationSo,itisaLinearequation
b) Given \: 12x^{2} - 7 = 0b)Given12x2−7=0
\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)
\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.
c) Given \: equation : 3x^{2}+11x+14=x(3x+5x)c)Givenequation:3x2+11x+14=x(3x+5x)
\implies 3x^{2}+11x+14= x\times 8x⟹3x2+11x+14=x×8x
\implies 3x^{2}+10x+14= 8x^{2}⟹3x2+10x+14=8x2
\implies 3x^{2}+10x+14-8x^{2}=0⟹3x2+10x+14−8x2=0
\implies -5x^{2}+10x+14=0⟹−5x2+10x+14=0
\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)
\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.
d) Given \: equation : -x^{2}+11x-18 = 0d)Givenequation:−x2+11x−18=0
\blue { ( Degree \: of \: the\: equation \:is \: 2 )}(Degreeoftheequationis2)
\green {So, it \:is \:a \: Quadratic\: equation.}So,itisaQuadraticequation.
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