Question

समीकरण 2x2 - 7x+3=0 के मूल. द्विघात सूत्र का उपयोग करके ज्ञात कीजिए।​

Answer 1

The roots of the equation 2x2 - 7x + 3 = 0. Find out using the quadratic formula.

$\textbf{Given:}$

$\textsf{Quadratic equation is}$

$\mathsf{2x^2-7x+3=0}$

$\textbf{To find:}$

$\textsf{Roots of the given quadratic equation}$

$\textbf{Solution:}$

$\textbf{Formula used:}$

$\boxed{\begin{minipage}{8cm} \mathsf{The\;roots\;of\;the\;equation\;ax^2+bx+c=0\;are}\\\\\mathsf{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}} \end{minipage}}$

$\mathsf{Consider,}$

$\mathsf{2x^2-7x+3=0}$

$\textsf{Roots of the equation is found by using quadratic formula}$

$\mathsf{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

$\mathsf{x=\dfrac{7\pm\sqrt{(-7)^2-4(2)(3)}}{2(2)}}$

$\mathsf{x=\dfrac{7\pm\sqrt{49-24}}{4}}$

$\mathsf{x=\dfrac{7\pm\sqrt{25}}{4}}$

$\mathsf{x=\dfrac{7\pm\,5}{4}}$

$\mathsf{x=\dfrac{7+5}{4},\;\dfrac{7-5}{4}}$

$\mathsf{x=\dfrac{12}{4},\;\dfrac{2}{4}}$

$\mathsf{x=3,\;\dfrac{1}{2}}$

$\therefore\mathsf{Roots\;are\;3\;\&\:\dfrac{1}{2}}$

$\textbf{Find more:}$

Using the quadratic formula to solve 5x = 6x2 – 3, what are the values of x

https://brainly.in/question/14911682

Using the quadratic formula, solve the equation a square b square x square - (4b power 4-3apower4)x-12a square b square =0

https://brainly.in/question/5074987

A(x^2 + 1) = (a^2+ 1) x, a + 0 solve by formula method​

https://brainly.in/question/16238292