Question

समीकरण एक्स स्क्वायर प्लस वन होल स्क्वायर माइनस एक्स स्क्वेयर इक्वल टू जीरो​

Answer 1

x = -$\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$, $\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$

• An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
• Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information, we are given that,

$(x^{2} +1)^{2} -x^{2} =0$

Or, $(x^{2} +x+1)(x^{2} -x+1)=0$

Then, x = -$\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$, $\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$

Hence, the solutions are,  x = -$\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$, $\frac{1}{2}$±$i\frac{\sqrt{3} }{2}$

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