Question

समीकरणे सोडवा: $\frac{b + (b+1) + (b+ 2)}{4} = 21$

Answer 1

Answer:

Step-by-step explanation:

Answer 2

समीकरणे सोडवा: $\frac{b + (b+1) + (b+ 2)}{4} = 21$

$\frac{b + b + 1 + b + 2}{4} = 21 \\ \\ 3b + 3 = 21 \times 4 \\ \\ 3b + 3 = 84 \\ \\ 3b = 84 - 3 \\ \\ 3b = 81 \\ \\ b = \frac{81}{3} \\ \\ b = 27$

समीकरण हल: b = 27