Question

समान्तर श्रेणी 1/9,4/9,7/9,---------का 12 वाँ पद ज्ञात कीजिए​

Answer 1

Answer:

$\frac{34}{9}$

Step-by-step explanation:

$a_{1}$ = $\frac{1}{9}$ and common difference (cd) = $\frac{4}{9}$ - $\frac{1}{9}$ = $\frac{3}{9}$ = $\frac{1}{3}$

12th term $A_{12}$ = a + ( 12 -1 ) d

                       = a + 11d

                       = $\frac{1}{9}$ + 11×$\frac{1}{3}$

                        = $\frac{1}{9}$ + $\frac{11}{3}$

                        = $\frac{34}{9}$