समिश्र संख्या z=-√3+i का मापांक और कोणांक ज्ञात कीजिये
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Step-by-step explanation:
Here,
z = -sqrt(3) + i
<br> Comparing it with polar form, we get,<br>
rcostheta = -sqrt3 and rsintheta = 1
<br> Squaring and adding these two terms, we get,<br>
r^2cos^2theta+r^2sin^2theta = 4
<br>
r^2(cos^2theta+sin^2theta) = 4
<br>
r^2 = 4=> r = 2
<br> So, modulus is
2
.<br> Now,
rsintheta = 1=>sintheta = 1/2
<br>
theta = pi/6
<br> As
costheta
is negative and
sintheta
is positive, theta lies in 2nd quadrant.<br> So,
theta = pi-pi/6 = (5pi)/6
<br>
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