समांतर श्रेणी -12,-5,2,9,16,23,का २० वॉ पद ज्ञात करो।
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Answer:
121
Step-by-step explanation:
a= -12 , d = a2 -a1 = - 5 - ( -12) = 7
n= 20
an = a+(n-1)d
n = 20
a20 = a + ( 20 - 1)d
= -12 + 19d
= -12 + 19 × 7
= - 12 +133
= 121
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