Question

समांतर श्रेणी -12,-5,2,9,16,23,का २० वॉ पद ज्ञात करो। ​

Answer 1

Answer:

121

Step-by-step explanation:

a= -12 , d = a2 -a1 = - 5 - ( -12) = 7

n= 20

an = a+(n-1)d

n = 20

a20 = a + ( 20 - 1)d

= -12 + 19d

= -12 + 19 × 7

= - 12 +133

= 121