Math, asked by bhasitadasari2291, 11 months ago

समांतर श्रेणी 8, 3, -2 के प्रथम 22 पदों का योग ज्ञात कीजिए।

Answers

Answered by Anonymous

2

Step-by-step explanation:

S(22) = 22/2 { 2(8)+(22-1)(-5)}

= 11 { 16 + 21(-5)}

= 11(16-105)

= 11*(-89) = -979

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