Question

same force acts on two different masses 3 kg and 5kg initially at rest.The ratio of times required to acquire same final velocity is?

Answer 1

initial velocity = u = 0
final velocity = v

v = 0 + at = at = (F/m)t = F*(t/m)

let the velocities be v1=v2=v

$\frac{v_1}{v_2} = \frac{t_1/m_1}{t_2/m_2} \\ \\ 1= \frac{t_1/3}{t_2/5} \\ \\ \frac{t_1}{3} = \frac{t_2}{5} \\ \\ \frac{t_1}{t_2} = \frac{3}{5}$

So the ratio of times = 3/5

Answer 2

Explanation:

initial velocity = u = 0

final velocity = v

v = 0 + at = at = (F/m)t = F*(t/m)

let the velocities be v1=v2=v

\begin{lgathered}\frac{v_1}{v_2} = \frac{t_1/m_1}{t_2/m_2} \\ \\ 1= \frac{t_1/3}{t_2/5} \\ \\ \frac{t_1}{3} = \frac{t_2}{5} \\ \\ \frac{t_1}{t_2} = \frac{3}{5}\end{lgathered}

v

2

v

1

=

t

2

/m

2

t

1

/m

1

1=

t

2

/5

t

1

/3

3

t

1

=

5

t

2

t

2

t

1

=

5

3

So the ratio of times = 3/5