Question

Same mass of coper is drawn into 2 wires of 1mm thick and 3mm thick. Two wires are connected in series and current is passed. Heat produced in the wires is the ratio of_________________?

Answer 1

Let the resistance of wire I ( 1mm thick) and that of wire II ( 3mm thick) be x and y respectively.

We know,

$\qquad \boxed{H = I^2 R t}$

Ratio of Heat = $\frac{\mathtt{Heat \: produced\: in \: wire \: I}}{\mathtt{Heat \: produced \: in \: wire \: II}}$

$\Rightarrow \quad \frac{I^2 x t}{I^2 y t} \qquad \qquad$ ( Resistance of wire I is x and that of wire II is y )

$\Rightarrow \quad \frac{\red{\cancel{I^2}} \times x \times \red{\cancel{t}}}{\red{\cancel{I^2}} \times y \times \red{\cancel{t}}} \\ \Rightarrow \quad \frac{x}{y}$

Therefore, The ratio of heat produced in both the wires is the ratio of thier RESISTANCE.

Answer 2

Answer:

above answer was correct

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