Same net force is applied on two different objects ofmasses m and 3m. If x and y are the magnitudes oftheir acceleration respectively, then the ratioxywillbe(1) 1 : 3 (2) 1 : 1(3) 3 : 1 (4) 9 : 1
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Net force= m*x = 3m*y
mx=3my
x/y = 3m/3
x:y = 3:1
Answer is (3) 3:1
mx=3my
x/y = 3m/3
x:y = 3:1
Answer is (3) 3:1
Answered by
1
(1) 1:3
F=MA GIVEN MASSES M AND 3M RESPCTIVELY.
SO
MA/3MA =1:3
F=MA GIVEN MASSES M AND 3M RESPCTIVELY.
SO
MA/3MA =1:3
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