Chemistry, asked by kapilsachdeva4238, 11 months ago

Same quantity of electricity is being used to liberate iodine (at anode) and a metal x (at cathode). The mass of x deposited is 0.617g and the iodine is completely reduced by 46.3 cc of 0.124m sodium thiosulphate find the equivalent mass of x.

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Answered by Anonymous
0

Answer:

The mass of metal M liberated is 0.617 g and the liberated iodine is completely reduced by 46.3 mL of 0.124 M sodium

Answered by Anonymous
0

Answer:

Same quantity of charge is being used to liberate iodine (at anode) and a metal

(at cathode). The mass of metal

liberated is

and the liberated iodine is completely reduced by

of

sodium thio-sulphate. Calculate equivalent weight of metal. Also calculate the total time to bring this change if

ampere current passed through solution of metal iodide.

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