Question

same question here
A father is twice old as his son .the sum of the ages is 99 .find their ages​

Answer 1

Answer:

hey mate here is ur answer

Step-by-step explanation:

Given sum of their ages =99

let the son age be x

so fathers age will be 2x

now x+2x=99

3x=99

x=99/3

33

×=33

so son age is 33

now father age will be2x

so2×33=66

hope it will help you

thankyu

Answer 2

Answer:

let the age of son be x

father age = 2x

ages sum = 99

so,

x+2x=99

3x=99

x=99/3

x=33

age of son=x=33 years

age of father=2x=33*2=66 years