Math, asked by Anshika01316, 6 months ago


Sameer bought 1600 bananas at 3.75 a dozen. He sold 900 of them at 2 for ruppes1 and the remaining at
5 for ruppes 2. Find his gain or loss per cent.​

Answers

Answered by suhani40020
2

Answer:

46%

Step-by-step explanation:

Sameer bought 1600→cl 3.75 a dozen

cost for which sameer bought 1600 bananas

=

12

1600

=3.75=

12

16×375

=Rs500

He sold 900 bananas at Rs 1 for two bananas

Amount to which he sold 900 bananas =

2

900

×1

Rs=450

The remaining 700 are sold at Rs 2 for five

Amount to which be sold 700 bananas =

5

700

.2

Rs=280

Gain =(

Actualcost

soldcost−Actualcost

)×100

=(

500

450+280−500

)×100=

5

230

=46 %

Answered by AfeefaAnoop
0

Answer:

Cost of 12 bananas = rs 3.75

cost of 1 banana = 3.75/12

cost of 1600 bananas = 1600*3.75/12= rs. 500

s p. of bananas

first case,

s.p. of 2 bananas = rs. 1

s.p. of 1 banana = rs. 0.5

s p. of 900 bananas = rs.0.5*900 = 450

second case,

no.of bananas = 1600-900 = 700

cost of 5 bananas = rs. 2

cost of 1 banana = rs.0.4

cost of 700 bananas = rs 0.4*700= 280

total selling price = 450+280

= 730

c.pSo, their is gain

gain percent = x

s.p.-c.p./c. p.*100 = x

730-500/500*100=x

230/500*100=46

x = 46%

Therefore, gain percent = 46%

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