Question

Sameer has a gift box of length 15cm, breadth 10cm and height 12cm. Find the

volume of the box​
​

Answer 1

Diagram :

$\setlength{\unitlength}{0.74 cm}\begin{picture}(12,4)\linethickness{0.4mm}\put(6,6){\line(1,0){5}}\put(6,9){\line(1,0){5}}\put(11,9){\line(0,-1){3}}\put(6,6){\line(0,1){3}}\put(4,7.3){\line(1,0){5}}\put(4,10.3){\line(1,0){5}}\put(9,10.3){\line(0,-1){3}}\put(4,7.3){\line(0,1){3}}\qbezier(6,6)(4,7.3)(4,7.3)\qbezier(6,9)(4,10.2)(4,10.3)\qbezier(11,9)(9.5,10)(9,10.3)\qbezier(11,6)(10,6.6)(9,7.3)\put(8,5.5){\sf{15 cm}}\put(3.8,6.3){\sf{10 cm}}\put(11.2,7.5){\sf{12 cm}}\end{picture}$

Given :

• Sameer has a gift box of length 15cm, breadth 10cm and height 12cm.

To Find :

• Find the volume of the box

Solution :

$\underline{\bigstar\:\textsf{According to the given Question :}}$

$:\implies\sf \: \: \: \: \: \: \: \: \: Volume\:of\:Box=Length \times Breadth \times Height\\\\\\:\implies\sf \: \: \: \: \: \: \: \: \: Volume = 15 \:cm \times 10 \:cm \times 12 \:cm\\\\\\:\implies\: \: \: \: \: \: \: \: \: \: \underline{\boxed{\sf Volume = 1800 \:{cm}^{3} }}$

⠀

$\therefore\:\underline{\textsf{Hence, Volume of the Box is \textbf{1800 cm ^\text3 }}}.$

$\rule{180}{1.5}$

$\boxed{\begin{minipage}{6 cm}\underline{\text{Formulae Related to Cuboid :}}\\ \\{\textcircled{\footnotesize\textsf{1}}} \:\:\sf CSA = 2(Length + Breadth)\times\:\sf Height\\\\{\textcircled{\footnotesize\textsf{2}}} \: \:\sf TSA=2(lb+bh+hl)\\ \\{\textcircled{\footnotesize\textsf{3}}} \: \:Volume=Length\times Breadth\times Height\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Diagonal=\sqrt{l^2+b^2+h^2}\end{minipage}}$

Answer 2

Answer:

hi myself mayank i can not help you