Chemistry, asked by piyub12345, 1 year ago

Sameer took two test tubes and labelled them A and B. In test tube A, he put a substance
‘X’ and added dilute HCl. In test tube B, he put substance ‘Y’ and added dilute HCl. Sameer
observed the formation of a chloride in test tube B with evolution of a gas. No chemical
reaction was observed in test tube A.
a) Identify the test tubes containing metal and non-metal

Answers

Answered by suhas90
4
in test tube b
Fe +2hcl =fecl2 +h2
but in test tube a
cute +hcl =no reaction

piyub12345: what is cute here?
piyub12345: I mean cute +hcl
Answered by anvitanvar032
0

Answer:

The correct answer of this question is  it has a high SOP value.

Explanation:

Given - Sameer took two test tubes and labeled them A and B. In test-tube A, he put a substance ‘X’ and added dilute HCl. In test-tube B, he put substance ‘Y’ and added dilute HCl.

To Find - a) Identify the test tubes containing metal and non-metal.

A. No chemical reaction occurs in the test tube, according to the question. In the reactivity series, X must be below Cl.

As a result, it has a high SOP value.

B. Chloride formation suggests.

In a reactivity series with a low SOP value, Y must be higher than cl.

as an example

Zn +2HCL-----> 2ZNCl+H2

#SPJ2

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