Sameer took two test tubes and labelled them A and B. In test tube A, he put a substance
‘X’ and added dilute HCl. In test tube B, he put substance ‘Y’ and added dilute HCl. Sameer
observed the formation of a chloride in test tube B with evolution of a gas. No chemical
reaction was observed in test tube A.
a) Identify the test tubes containing metal and non-metal
Answers
Answered by
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in test tube b
Fe +2hcl =fecl2 +h2
but in test tube a
cute +hcl =no reaction
Fe +2hcl =fecl2 +h2
but in test tube a
cute +hcl =no reaction
piyub12345:
what is cute here?
Answered by
0
Answer:
The correct answer of this question is it has a high SOP value.
Explanation:
Given - Sameer took two test tubes and labeled them A and B. In test-tube A, he put a substance ‘X’ and added dilute HCl. In test-tube B, he put substance ‘Y’ and added dilute HCl.
To Find - a) Identify the test tubes containing metal and non-metal.
A. No chemical reaction occurs in the test tube, according to the question. In the reactivity series, X must be below Cl.
As a result, it has a high SOP value.
B. Chloride formation suggests.
In a reactivity series with a low SOP value, Y must be higher than cl.
as an example
Zn +2HCL-----> 2ZNCl+H2
#SPJ2
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