sameer went on his bike from delhi to gurgaon at a speed of 60km/hr and came back at a speed of 40 km/hr . what is the average speed
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let the distance be x[same from delhi -gurgaon and vice versa]
so..
while going..........
,d=x
speed=60km/hr
time=d/s=x/60hrs
while coming back.....
d=x
speed=40km/hr
time=d/s
=x/40hrs
now ,avg speed=total distance /total time taken
=x+x/x/40+x/60
=2x/5x/120
=48km/hr
so..
while going..........
,d=x
speed=60km/hr
time=d/s=x/60hrs
while coming back.....
d=x
speed=40km/hr
time=d/s
=x/40hrs
now ,avg speed=total distance /total time taken
=x+x/x/40+x/60
=2x/5x/120
=48km/hr
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