Question

samikaran Mein Se pratyek samikaran Ke Char cal likhiye
a. πx+y=9​

Answer 1

Answer:

Given

−

\pink\longrightarrow\small\sf \pink{The \: length \: of \: a \: rectangular \: field \: is \: 60 m}⟶Thelengthofarectangularfieldis60m⟶Thelengthofarectangularfieldis60m⟶Thelengthofarectangularfieldis60m

\pink\longrightarrow\small\sf \pink{The \: breadth \: is \: 2/3 \: of \: its \: length }⟶Thebreadthis2/3ofitslength < /p > < p > \bf \underline{\underline \orange{To \: Find}} -⟶Thebreadthis2/3ofitslength⟶Thebreadthis2/3ofitslength</p><p>

ToFind

−

ToFind

−

\pink\longrightarrow\small\sf \purple{Area \: of \: Rectangular \: Field }⟶AreaofRectangularField < /p > < p > \large\bf\underline{\underline \green{Solution}} -⟶AreaofRectangularField⟶AreaofRectangularField</p><p>

Solution

−

Solution

−

Here,

\purple\longrightarrow\small\sf \pink{Length} = \purple{L}⟶Length=L⟶Length=L⟶Length=L

[\purple\longrightarrow\small\sf \pink{Breadth}=\purple{B}⟶Breadth=B

Firstly We Find The Breadth.

We known that

Be is 2/3 of it's length.

So,

\blue\Longrightarrow\small \sf \pink{B} = \purple {L× \dfrac{2}{3}}⟹B=L×⟹B=L×

3

2

⟹B=L×

3

2

\blue\Longrightarrow\small \sf \pink{B} = \purple {\dfrac{2L}{3}}⟹B=⟹B=

3

2L

⟹B=

3

2L

\blue\Longrightarrow\small\sf \pink{B}= \purple{\dfrac{2 \times 60}{3} }⟹B=⟹B=

3

2×60

⟹B=

3

2×60

\blue\Longrightarrow\small\sf\pink{B}=\purple{\cancel\dfrac{120}{3}}⟹B=⟹B=

3

120

⟹B=

3

120

\blue\Longrightarrow\small\sf \pink{B} = \purple{40m}⟹B=40m⟹B=40m⟹B=40m

Now, we know that the field's breath is 40 cm.

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

Now,we find the area of Field. < /p > < p > {\green\Longrightarrow{\small \sf \red{Area \: of \: Rectangle \: is} = \blue{Length × Breadth }}}Now,wefindtheareaofField.</p><p>⟹AreaofRectangleis=Length×Breadth }⟹AreaofRectangleis=Length×Breadth

So,

{\green\Longrightarrow\small \sf \red{Area \: of \: Rectangular \: Field} = \blue{60 \times 40} }⟹AreaofRectangularField=60×40

{\green\Longrightarrow\small \sf \red{Area \: of \: Rectangular \: Field \: is } = \blue{2400 \:{m}^{2}}}⟹AreaofRectangularFieldis=2400m

2

}⟹AreaofRectangularFieldis=2400m

2

Therefore -

The Area of Rectangular Field is 2400 m².

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\bf\underline{\underline \orange{More \: Useful \: Formulas}}

MoreUsefulFormulas

MoreUsefulFormulas

{\blue\longrightarrow\small\sf \purple{Area\:of \:Rectangle}= \pink{ Length × Breadth} }⟶AreaofRectangle=Length×Breadth

{\blue\longrightarrow\small\sf \purple{Perimeter \:of \:Rectangle}= \pink{ 2(Length × Breadth)}}⟶PerimeterofRectangle=2(Length×Breadth) }⟶PerimeterofRectangle=2(Length×Breadth