Question

Sampath applies a force of 500N in pushing a table such that work done by him is 250J.

Calculate the displacement produced in the table​

Answer 1

$\huge\green{\boxed{\underline{ANSWER}}}$

$➲$ Displacement = 0.5 m

$\purple{\boxed{\underline{EXPLANATION}}}$

GIVEN THAT:

$➲$ Sampath applies a force of 500N in pushing a table.

$➲$ work done by him = 250j

FORMULA:

$➲$ W = F × S

Where,. • w = work done

• F = Applied force

s • Displacement

SOLUTIONS:

$&#10145 \: \: work \: done \: = f \times s \\ &#10145 \: \: 250 = 500 \times s \: \: \: \: \: \: \: \: \: \: \: \\ &#10145 \: \: s = \cancel\frac{250}{500} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ &#10145 \: \: s = 0.5 \: m \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

$➨$ Displacement = 0.5 m