Question

Sampath applies a force of 500N in pushing a table such that work done by him is 250J.
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Answer 1

Answer:

Let displacement be 'x'

Work-done = Force × Displacement

250 J = 500 N × x m

x m = 250 J / 500 N

x m = 0.5 m

∴ Displacement = 0.5 m