Question

SAMPLE 4 Seven years ago Varun's age was five times the square of Swati's age. Three years hence
Swati's age will be two fifth of Varun's age. Find their present ages. by using present age of swati as x​

Answer 1

Step-by-step explanation:

Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x2 years.

Swati's present age =(x+7) years, Varun's present age=(5x2 +7) years

Three years hence, we have

Swati's age (x+7+3) years =(x+10) years

Varun's age =(5x2+7+3)=(5x2+10)

It is given that three years hence Swati's age wil be 2÷5 of Varun's age

∴x+10= 2÷5 (5x2+10)

⇒x+10=2x2 +4

⇒2x 2 −x−6=0

⇒2x 2 −4x+3x−6=0

⇒(2x+3)(x−2)=0

⇒x−2=0⇒x=2

Hence Swati's present age =(2+7) years =9 years

Varun's present age =(5×x 2+7) years =27 years

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