SAMPLE 4 Seven years ago Varun's age was five times the square of Swati's age. Three years hence
Swati's age will be two fifth of Varun's age. Find their present ages. by using present age of swati as x
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Step-by-step explanation:
Seven years ago. let Swati's age be x years. Then, seven years ago Varun's age was 5x2 years.
Swati's present age =(x+7) years, Varun's present age=(5x2 +7) years
Three years hence, we have
Swati's age (x+7+3) years =(x+10) years
Varun's age =(5x2+7+3)=(5x2+10)
It is given that three years hence Swati's age wil be 2÷5 of Varun's age
∴x+10= 2÷5 (5x2+10)
⇒x+10=2x2 +4
⇒2x 2 −x−6=0
⇒2x 2 −4x+3x−6=0
⇒(2x+3)(x−2)=0
⇒x−2=0⇒x=2
Hence Swati's present age =(2+7) years =9 years
Varun's present age =(5×x 2+7) years =27 years
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