Question

Sample of caco3 is 50% pure on heating 1.12l of co2 at stp is obtained residue left

Answer 1

Answer:

Total mass of residue left after heating.

Decomposition (reaction) of  :-

From this reaction, it is clear that 1 mole of  gives 1 mole of CaO and 1 mole of .

we can say the moles of  produced is equal to moles of  consumed.

Now, according to the question,

At STP 1 mole of  = 22.4 L

Then, no. of moles of  =

So, no. of moles of  = 0.05

Molar mass of  = 100 g/mole

We have 0.5 mole = 0.5 × 100 = 5 g

Now, molar mass of CaO = 56 g/mole

Total Mass of CaO remaining =

Total mass of residue left = 5.0 + 2.8 = 7.8 g

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Explanation: