Question

Sample Problem 6. A force of 5 newtons gives a mass m, an acceleration of 8 m/s2, and a mass my an
acceleration of 24 m/s2. What acceleration would it give if both the masses are tied together?​

Answer 1

(I) In the first case-

Force , F =5 N

Mass , m=m1

And , Acceleration, a =8m/s square

Now , F=m×a

So , 5=m1 ×8

And , m1 =5/8 kg

m1= 0.625kg

THUS , mass m1 is 0.625kg.

(ii) In second case-

Force , F=5N

Mass, m =m2

And , Acceleration , a= 14m/s square

Now , F=m×a

So , 5 = m2×24

And , m2=5/24kg

m2 = 0.208 kg

Thus , Mass m2 is 0.208 kg

(iii) In third case

Force , F = 5N

Total mass , m= m1+ m2

=0.635+0.208

=0.833 kg

And , Acceleration,a=?

Now Pitt these values in the relation

F=m×a

We get , 5=0.833×a

a=5/0.833

a=6m/s square

Thus , if both the masses are tied together, then the acceleration would be 6m/s square.

Answer 2

(I) In the first case-

Force , F =5 N

Mass , m=m1

And , Acceleration, a =8m/s square

Now , F=m×a

So , 5=m1 ×8

And , m1 =5/8 kg

m1= 0.625kg

THUS , mass m1 is 0.625kg.

(ii) In second case-

Force , F=5N

Mass, m =m2

And , Acceleration , a= 14m/s square

Now , F=m×a

So , 5 = m2×24

And , m2=5/24kg

m2 = 0.208 kg

Thus , Mass m2 is 0.208 kg

(iii) In third case

Force , F = 5N

Total mass , m= m1+ m2

=0.635+0.208

=0.833 kg

And , Acceleration,a=?

Now Pitt these values in the relation

F=m×a

We get , 5=0.833×a

a=5/0.833

a=6m/s square

Thus , if both the masses are tied together, then the acceleration would be 6m/s square.