sana had rupee 85 1/2. out of this she purchased a book for 43 1/8 and a pen for 21 1/4. how much money is left with her ?
Answers
Answered by
22
Solution :-
First, we have to find the image distance :
\implies \sf \dfrac{- v}{u} =\: \dfrac{3\cancel{h_o}}{\cancel{h_o}}⟹
u
−v
=
h
o
3
h
o
\implies \sf \dfrac{- v}{u} =\: 3⟹
u
−v
=3
By doing cross multiplication we get,
\implies \sf - v =\: 3u⟹−v=3u
\implies \sf \bold{\purple{v =\: - 3u}}⟹v=−3u
Now, we have to find the object distance :
Given :
Image Distance (v) = - 3u
Focal Length (f) = - 20 cm
\longrightarrow \sf \dfrac{1}{- 20} =\: \dfrac{1}{- 3u} + \dfrac{1}{u}⟶
−20
1
=
−3u
1
+
u
1
\longrightarrow \sf \dfrac{1}{- 20} =\: \dfrac{- 1 + 3}{3u}⟶
−20
1
=
3u
−1+3
\longrightarrow \sf \dfrac{1}{- 20} =\: \dfrac{2}{3u}⟶
−20
1
=
3u
2
Answered by
3
Answer:
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