Question

sana is senior to mona by 18 years after 6 years sana will be twice as old as mona find mona s present age

Answer 1

Step-by-step explanation:

Let the age of Mona be x

Therefore, age of Sana is 18 + x

after six years, age of Sana will be 6+18+x

as per the condition,

6+18+x=2*x

24+x=2x

24=3x

3x=24

x=24/3

x=8

Therefore the age of Mona is 8

Answer 2

Given,

Sana is senior to Mona by 18 years after 6

years Sana will be twice as old as Mona.

To find,

Present age of Mona.

Let,

Present age of Sana be 'x'.

and the present age of Mona be 'y'.

As it is given Sana is senior to Mona by 18 years.

Sana's age = Mona's age + 18

i.e. X = Y+18..........(i)equation

After 6 years,

Sana's age = X+6

Mona's age = Y+6

Then, Sana will be twice as old as Mona.

x + 6 = 2 (y+6)

x + 6 = 2y+12

x = 2y+12-6

x = 2y+6............(ii)equation

From boththe equation,

2y+6 = y+18

2y-y = 18-6

Y = 12

Now substitute the value of y in equation i.

X = Y+18

X = 12+18

X = 30

Therefore the present age of Sona is X = 30 years and the present age of Mona is Y = 12 Years.

Verification:

Substitute the values of x and y in one of the equations such that L.H.S = R.H.S.

X = Y+18

30 = 12+18

30 = 30

L.H.S = R.H.S