Question

sand and cement are in ratio 6:5 in a mixture weighing 671 kg.how much sand must be added to the mixture ,so as to make the ratio 8:5.?

Answer 1

Answer:122

Step-by-step explanation:

Given ratio:- 6:5

Total weight of mixture 671kg

Sand:-366kg

Cement:-305kg

If the ratio is converted to 8:5 then the weight of sand is 488 kg

Sand added = 488-366 =122kg

Answer 2

Answer:

122 kg of sand must be added to the mixture.

Step-by-step explanation:

Given : Sand and cement are in ratio 6:5 in a mixture weighing 671 kg.

To find : How much sand must be added to the mixture ,so as to make the ratio 8:5.?

Solution :

Let the ratio be 'x'

Sand and cement are in ratio 6:5 in a mixture weighing 671 kg.

So, the sand and cement is 6x and 5x.

$6x+5x=671$

$11x=671$

$x=\frac{671}{11}$

$x=61$

So, Sand is $6x=6\times 61=366$

Cement is $5x=5\times 61=305$

The ratio of sand to cement is 366 : 305

Let x kg of sand must be added to the mixture ,so as to make the ratio 8:5.

i.e. $\frac{366+x}{305}=\frac{8}{5}$

$366+x=\frac{8\times 305}{5}$

$366+x=488$

$x=488-366$

$x=122$

Therefore, 122 kg of sand must be added to the mixture.