Question

Sand drops from a stationary hopper at the rate of 5 kgs- onto a conveyor belt moving with
constant speed of 2 m/s What is the force required to keep the belt moving and what is the power
delivered by the motor moving the belt? (impulse J = Ft=my)
a) 10 N 20 W
b) 20 N, 10 W
c) 10 N, 10 W
d) 20 N,20 W
I want with solution
and mark you brainliest friends please and I follow you ​

Answer 1

Answer:

OK NO WORRIES

Explanation:

Here mass of sand drops at a rate of 5kg/s

⟹

dt

dm

​

=5kg/s

Velocity of conveyor belt , v=2 m/s

Force required to keep th ball moving , F=

dt

d

​

(mv)=v

dt

dm

​

=5×2=10 N

Power  delivered by the motor ,P=F⋅v=10×2=20 W

GAO MIKADO ⚡️