Question

sand is falling on a conveyor belt at rate of 5kg/s. the extra power required to move the belt with a velocity of 6 m/s is _____ ?

Answer 1

The force required to keep the belt moving is equal to the rate of increase of horizontal momentum of the sand.

Or, F = rate of change of mass × velocity change

=> F = (5 kg/s)(6 m/s)

=> F = 30 N

Now,

Power = work done per second

=> P = force × rate of displacement

=> P = Fv = (30 N)(6 m/s)

=> P = 180 W

Answer 2

Answer:

P = 180 W

Explanation:

F = rate of change of mass × velocity change

F = (5 kg/s)(6 m/s)

F = 30 N

P = force × rate of displacement

P = Fv = (30 N)(6 m/s)

P = 180 W