Math, asked by pij56, 1 year ago

Sandeep age after 6 years will be three seventh of his father's age at that time 10 years ago the ratio of their ages was 1 ratio 5 what is Sandeep father's age at present​

Answers

Answered by neha0701
1

let son be x and father be y

x-3y=-6

5x-y=40

by elimination method

y=5

Answered by Anonymous
6

Answer :- 50 years

Explanation :-

The ratio of Sandeep and his father 10 year ago is 1:5

Therefore,

Let the age of Sandeep be x and Sandeep father be 5x respectively.

According to the given condition

Sandeep age after 6 years will be three seventh of his father's age.

x + 16 = ( 3/7 )(5x + 16)

7x + 112 = 15x + 48

8x = 64

x = 64/8

x = 8

Sandeep father's present age will be,

5x + 10

Substituting x = 8

5(8) + 10

40 + 10

= 50 years

Therefore, The age of Sandeep father's is 50.


Anonymous: In the first part of the question it is said :- age of Sandeep's is 3/7 times the age of Sandeep's Farther after 6 years
Anonymous: So let the age of Sandeep be x years 10 years ago ,, then age of father 10 years ago = 5x
pij56: yeah
Anonymous: Now present age
Anonymous: = x + 10 and 5x +10
Anonymous: and age after 6 years = x + 10 + 6 , and 5x + 10 + 6
Anonymous: = x + 16 and 5x + 16
Anonymous: Now it's given in the answer !
pij56: okay..
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