Math, asked by shravan5491, 11 months ago

Sandeep filled water in 4/7 of an empty tank. After that Ramakant filled 1/4 part more of the same tank. Than umesh used 3/14 part of water. If the tank has maximum capacity of 560 liters, how many liters of water will be left in the tank?​

Answers

Answered by GaneshonBrainly
7

Answer:

\frac{340}{560} litres of water will be left in the tank.

Step-by-step explanation:

First, make sure the denominators of all fractions are over 560, to make calculations easier.

Sandeep filled \frac{4}{7}  = \frac{320}{560} (7 x 80 = 560; 4 x 80 = 320)

Ramakant filled \frac{1}{4} = \frac{140}{560} ( 4 x 140 = 560; 1 x 140 = 140)

The amount of water in the tank as of now:  \frac{140+320}{560} = \frac{460}{520}

Umesh uses \frac{3}{14} = \frac{120}{560} (14 x 40 = 560; 3 x 40 = 120)

The amount of water that remains in the tank is \frac{460}{520} - \frac{120}{560} = \frac{340}{560}

Answered by Anonymous
0

Answer:

Step-by-step explanation:Answer:

\frac{340}{560} litres of water will be left in the tank.

Step-by-step explanation:

First, make sure the denominators of all fractions are over 560, to make calculations easier.

Sandeep filled \frac{4}{7}  = \frac{320}{560} (7 x 80 = 560; 4 x 80 = 320)

Ramakant filled \frac{1}{4} = \frac{140}{560} ( 4 x 140 = 560; 1 x 140 = 140)

The amount of water in the tank as of now:  \frac{140+320}{560} = \frac{460}{520}

Umesh uses \frac{3}{14} = \frac{120}{560} (14 x 40 = 560; 3 x 40 = 120)

The amount of water that remains in the tank is \frac{460}{520} - \frac{120}{560} = \frac{340}{560}

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