Question

sandeep sahani
$x3 - 64y3$

Answer 1

Here's your answer :

(x)^3 - (4y)^3

Formula : (a-b) (a^2 + ab + b^2 )

= (x - 4y )(x^2 + 4xy + 16y^2 )

Hope this helps you. . .
THANK YOU. .

Answer 2

The answer is given below :

IDENTITY RULE :

a³ - b³ = (a - b) (a² + ab + b²)

SOLUTION :

Now,

x³ - 64y³

= x³ - (4y)³

= (x - 4y) {x² + (x × 4y) + (4y)²}

= (x - 4y) (x² + 4xy + 16y²),
which is the required factorization.

Thank you for your question.