Question

Sandeep was 6 years older than Sandhya. Five years ago, sandeep was three times as old as Sandhya. What are their present ages

Answer 1

Answer:

Sandhya is 8 years old and Sandeep is 14 years old

Step-by-step explanation:

Let Sandhya be x years old

Sandeep is x + 6 years old

5 years ago:

Sandhya = x - 5 years old

Sandeep = x + 6 - 5 = x + 1 years old

Solve x:

Five years ago, sandeep was three times as old as Sandhya

x + 1 = 3(x - 5)

x + 1 = 3x - 15

2x = 16

x = 8

Find their age:

Sandhya = x = 8 years old

Sandeep = x + 6 = 8 + 6 = 14 years old

Answer: Sandhya is 8 years old and Sandeep is 14 years old