Question

Sandeep, while driving to school, computer the average speed for his trip to 40 km/h -¹. On his return trip along the same route, there is less traffic and the average speed is 50 km/h-¹.what is the average speed for sandeep's trip?​

Answer 1

Explanation:

Fill in the blanks with appropriate words given in the bracket . ( Yesterday , today , week , month , year , tomorrow , fortnight , morning , night , afternoon , midnight , evening , noon , last night , last month , next year , last year , next week , last week , full moon day , new moon day , day before yesterday , day after tomorrow , week end )

Fill in the blanks with appropriate words given in the bracket . ( Yesterday , today , week , month , year , tomorrow , fortnight , morning , night , afternoon , midnight , evening , noon , last night , last month , next year , last year , next week , last week , full moon day , new moon day , day before yesterday , day after tomorrow , week end )

Fill in the blanks with appropriate words given in the bracket . ( Yesterday , today , week , month , year , tomorrow , fortnight , morning , night , afternoon , midnight , evening , noon , last night , last month , next year , last year , next week , last week , full moon day , new moon day , day before yesterday , day after tomorrow , week end )

Answer 2

Answer:

44.4km/hr

Explanation:

In this question, we are required to find the average speed when half the distance is travelled by 40km/h and the remaining half by 50km/h.

we can use 2nd case of average speed in which

average speed = $\frac{2uv}{(u+v)}$

here the values are

u =40 km/hr

v = 50km

putting the values

$\frac{2(40*50)}{(40+50)}$

= $\frac{2(2000)}{90}$

=$\frac{4000}{90}$=44.4km/hr

∴ the average speed will be 44.4km/hr