Question

sandhu is twice as old as Sushil. Five years ago, Sandhu was 4 times older than Sushil. find their present age.

Answer 1

Hiii friend,


Let the present age of Sushil be X years.

Then the age of Sandhu is 2X.

Before 5 years age of Sushil = (X-5) years.

Before 5 years age of Sandhu = (2X-5) years.

According to question,

2X-5 = 4(X-5)

2X-5 = 4X-20

4X-2X = 20-5

2X = 15

X = 15/2

Age of Sushil = X = 15/2

And,

Age of Sandhu = 2X = 2 × 15/2 = 15 years.

I think your question is incorrect because age will Never come in P/Q form.. So please correct your question first.